((x^2-9)/5)-((x^2-4)/15)=(1-2x)/3

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Solution for ((x^2-9)/5)-((x^2-4)/15)=(1-2x)/3 equation:


x in (-oo:+oo)

(x^2-9)/5-((x^2-4)/15) = (1-(2*x))/3 // - (1-(2*x))/3

(x^2-9)/5-((x^2-4)/15)-((1-(2*x))/3) = 0

(x^2-9)/5-((x^2-4)/15)-((1-2*x)/3) = 0

(x^2-9)/5+(-1*(x^2-4))/15+(-1*(1-2*x))/3 = 0

(3*15*(x^2-9))/(3*5*15)+(-1*3*5*(x^2-4))/(3*5*15)+(-1*5*15*(1-2*x))/(3*5*15) = 0

3*15*(x^2-9)-1*3*5*(x^2-4)-1*5*15*(1-2*x) = 0

30*x^2+150*x-345-75 = 0

30*x^2+150*x-420 = 0

30*x^2+150*x-420 = 0

30*(x^2+5*x-14) = 0

x^2+5*x-14 = 0

DELTA = 5^2-(-14*1*4)

DELTA = 81

DELTA > 0

x = (81^(1/2)-5)/(1*2) or x = (-81^(1/2)-5)/(1*2)

x = 2 or x = -7

30*(x+7)*(x-2) = 0

(30*(x+7)*(x-2))/(3*5*15) = 0

(30*(x+7)*(x-2))/(3*5*15) = 0 // * 3*5*15

30*(x+7)*(x-2) = 0

( 30 )

30 = 0

x belongs to the empty set

( x+7 )

x+7 = 0 // - 7

x = -7

( x-2 )

x-2 = 0 // + 2

x = 2

x in { -7, 2 }

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